(x^2-2x)^2-3=2(x^2-2x)

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Solution for (x^2-2x)^2-3=2(x^2-2x) equation:



(x^2-2x)^2-3=2(x^2-2x)
We move all terms to the left:
(x^2-2x)^2-3-(2(x^2-2x))=0
We calculate terms in parentheses: -(2(x^2-2x)), so:
2(x^2-2x)
We multiply parentheses
2x^2-4x
Back to the equation:
-(2x^2-4x)
We get rid of parentheses
-2x^2+(x^2-2x)^2+4x-3=0
We add all the numbers together, and all the variables
-2x^2+4x+(x^2-2x)^2-3=0
We move all terms containing x to the left, all other terms to the right
-2x^2+4x+(x^2-2x)^2=3

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